Curve staking

Curve stationing and the PT equals PC plus L trap

A 900 ft radius curve is stationed from its PI, with the 29.63 ft of chainage lost at the corner made explicit and every full station on the curve tabulated.

Recall· about 16 minutes by hand· 5 steps

Given

  • A simple circular curve with R = 900.00 ft and Δ = 41°18′00″.
  • Station of the PI = 87+42.36.
  • Alignment stationing runs ahead through the curve; there is no station equation on this alignment.
  • All distances are US survey feet.

Required

  • The stations of the PC and the PT.
  • The chainage difference between the true PT and the incorrect PI plus T.
  • The arc distance from the PC to each full station lying on the curve.

Work it through yourself before reading on - the solution below shows every step, so there is no way to skim it without giving the answer away.

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